Question

My Question no.2

What is the RMS speed of a nitrogen molecule at 27°C ?​

Answer 1

Answer:

We have R.M.S

μ =  in this M = Molar mass

And in the case of Nitrogen gas, T = 27 + 273 = 300 K.R = 8.314 (kg  /  )/ K mol

Since molar mass of Nitrogen gas = 28 gm/mol = 2.8 x  kg/mol

Hence μ =  = [ 3 x 8.314 x 300 / 2.8 x  ] = [267235.7 = 516.9m/s

So the r.m speed for oxygen gas at 0°C (273K) = 516.9 m/s

Answer 2

hey how much percentage u got in 10th?