Question

My Question-

Test the divisibility of the number chosen by 3, 4, 5, 6, 7, 8 and 9 (Explanation should be given)

Answer 1

Answer:

Divisibility rule of 3- sum of numbers should be divisible by 3 example 9810

9+8+1+0=99

9+9=18

1+8=9

As 9 is divisible by 3 so 9810 is divisble by 3

Divisibility rule of4- last 2 digits should be divisbile by 4 example 89712

As 12 is divisible by 4 so 89712 is also divisible by 4

Divisibility rule of 5- Last digit should be 0 or 5

example1234567890 as last digit is 0 so 1234567890 is also divisibile by 5

Divibility rule of 6- The number should be divisble by 2 and 3 example 18

as 18 is divisble by2 and 3 both so 18 is divisible by 6 also

Divisibilty rule of 7- Not found yet

divisblity rule of 8 - Last 3 digit should be divisible by 8

Divisibility rule of 9- Sum of all the digits should be divisible by 9