Question

My strongbox has a six-digit combination that contains no zeros
and no repeated digits. The first digit is one more than the
fourth digit, and the sixth digit is three more than the second digit.
The second and fifth digits add up to the first digit, and the third
and fifth digits add up to the fourth digit. If the sum of all six digits
of the combination is 31, what is my strongbox’s combination?​

Answer 1

Answer:

2nd digit and 4th digit could be (0,0), (1,1), (2,4), or (3,9) as anything higher than 3 will give a 2-digit number.

All the numbers add upto 31, one of them is 0 and 1st+5th is 13.

So the other 3 have to add upto 18. The largest digit can be 9 leaving 9 for the sum of 2nd and 4th digit which means they are (3,9).

So the number now is:

x3x9xx

1st digit is one more than the 2nd one.

43x9xx

1st and 5th add upto 13.

43x99x

Total sum is 31, one of them is 0. So the remaining number is 6

So now we have 2 possibilities:

430996 or

Answer 2

436990

Step-by-step explanation:

please mark as brainlist