Question

my test is going on
plz solve this
plz yaar solve kar de......✌​

Answer 1

hii sister

howdy!

given: in the triangle ABC ; AB = BC and AD = DC

TPT : ∠ADE=90 and AE=EC∠ADE=90 and AE=EC

proof:

in the triangle ADB and CDB;

AB = BC (given)

AD = CD (given)

and BD is common.

therefore by SSS congruency ; △ADB≅△CDB

therefore by CPCT congruency property;

∠ABD=∠CBD ............(1)and

∠ADB=∠CDB=180/2=90

∠ADE=∠CDB [vertically opposite angles]

∠ADE=90 deg

now in the triangles ABE and CBE;

AB=BC [given]

∠ABE=∠CBE [from eq(1)]

BE is common

therefore by SAS congruency

△ABE≅△CBE

AB=BC [given]

and by cpct, AE = EC.

i tried my best hope it helps you dear(•‿•)

Answer 2

Answer:

Hello sistah

Step-by-step explanation:

Hope it helps u please thank my answer