Question

My
the age of a mother and
ane 31 and 7 years respectively. The
number of years in which the mother age will be 3/2times that of the daughter is​

Answer 1

Answer:

After 41 years age of mother will be 3 / 2 times the age of daughter at that time.

Step-by-step explanation:

Given,

Present age of mother is 31 years.

Present age of daughter is 7 years.

Let, mother's age will be 3 / 2 times of the and of daughter after a years.

After a years :

= > Age of mother = Present age of mother + a years

= > Age of mother = 31 years + a years

= > Age of mother = ( 31 + a ) years

Similarly, after a years :

= > Age of daughter = Present age of daughter + a years

= > Age of daughter = 7 years + a years

= > Age of daughter = ( 7 + a ) years

According to the question : After a years

= > Age of mother = 3 / 2 x Age of daughter

= > ( 31 + a ) years = 3 / 2 x ( 7 + a ) years

= > 31 + a = 3 / 2 x ( 7 + a )

= > 2( 31 + a ) = 3( 7 + a )

= > 62 + 2a = 21 + 3a

= > 62 - 21 = 3a - 2a

= > 41 = a

Hence, after 41 years age of mother will be 3 / 2 times the age of daughter at that time.