My trip to work is 120 miles. If i go 8 mph faster than my usual speed, i'll get to work 30 minutes earlier. How long does my trip take, in hours, if i go my usual speed?
Answers
My trip to work is 120 miles. If I go 8 mph faster than my usual speed,
I'll get to work 30 minutes earlier.
How long is my trip if I don't speed up, in hours?
:
Let s = his normal speed
then
(s+8) = the faster speed
;
Change 30 min to .5 hrs
:
Write a time equation; time = dist/speed
normal time - faster time = .5 hrs
120%2Fs - 120%2F%28%28s%2B8%29%29 = .5
multiply by s(s+8), results:
120(s+8) - 120s = .5s(s+8)
120s + 960 - 120s = .5s^2 + 4s
arrange as a quadratic equation on the right
0 = .5s^2 + 4s - 960
multiply by 2 to get the coefficient of s^2 to = 1
s^2 + 8s - 1920 = 0
Factors to
(s-40)(s+48) = 0
the positive solution
s = 40 mph is his normal speed
then
120/40 = 3 hrs is his normal time
:
We can confirm this by finding the time at the faster speed
120/48 = 2.5 hrs, a half hour sooner