Question

My uncle went to panchla on his motorbike,worked there for an hour and returned home after 3hrs 30min.if he maintained a uniform speed of 40km/hr,let us find the distance of panchla from his home.

Answer 1

Given:

My uncle went to Panchla on his motorbike, worked there for an hour and returned home after 3hrs 30min

If he maintained a uniform speed of 40km/hr

To find:

The distance of Panchla from his home

Solution:

Let "D" km be the distance of Panchla from his home.

∴ The total distance covered by my uncle = 2D

Uniform Speed, S = 40 km/hr

Also, we have,

Uncle returned home from Panchla after = $3\frac{30}{60} \:hrs = 3\frac{1}{2} \:hrs = \frac{7}{2}\:hrs$

and

Uncle worked in Panchla for = 1 hr

∴ The time taken by my uncle to travel from home to Panchla and return back to home = $\frac{7}{2} - 1 = \frac{7 - 2}{2} = \frac{5}{2} \:hrs$

Now, we know the formula as:

$\boxed{\bold{Speed = \frac{Distance}{Time} }}$

Therefore, substituting the values of speed = 40 km/hr, distance = 2D & time = $\frac{5}{2} \:hrs$ in the above formula, we get

$40 = \frac{2D}{\frac{5}{2} }$

$\implies 2D = 40 \times \frac{5}{2}$

$\implies 2D = 20 \times5$

$\implies D = 10 \times 5$

$\implies \bold{D = 50\:km}$

Thus, the distance of Panchla form his home is 50 km.

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Answer 2

Answer:

50 , 3 30

40/

:

:

"" .

∴ = 2

, = 40 /

, ,

= 3\{30}{60} \: = 3\{1}{2} \: = \{7}{2}\:3

60

30

=3

2

1

=

2

7

= 1

∴ = \{7}{2} - 1 = \{7 - 2}{2} = \{5}{2} \:

2

7

−1=

2

7−2

=

2

5

, :

\{\{ = \{}{} }}

=

, = 40 /, = 2 & = \{5}{2} \:

2

5

,

40 = \{2}{\{5}{2} }40=

2

5

2

\ 2 = 40 \ \{5}{2}⟹2=40×

2

5

\ 2 = 20 \5⟹2=20×5

\ = 10 \ 5⟹=10×5

\ \{ = 50\:}⟹=50

, 50 .