Math, asked by 3785, 1 year ago

(n+1)^2-n^2 find the answer ​

Answers

Answered by pal69
1

(n+1)²-n²=n²+1+2n-n²=2n+1

Answered by Bianchi
1
(n + 1)² – n²

= (n + 1 + n) (n + 1 – n)

= (2n + 1) × 1

= 2n + 1


[ The identity used is a² - b² = (a + b) (a - b) ]



Hope it'll help.. :-)

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