(n+1)^2-n^2 find the answer
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(n+1)²-n²=n²+1+2n-n²=2n+1
Answered by
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(n + 1)² – n²
= (n + 1 + n) (n + 1 – n)
= (2n + 1) × 1
= 2n + 1
[ The identity used is a² - b² = (a + b) (a - b) ]
Hope it'll help.. :-)
= (n + 1 + n) (n + 1 – n)
= (2n + 1) × 1
= 2n + 1
[ The identity used is a² - b² = (a + b) (a - b) ]
Hope it'll help.. :-)
Bianchi:
Thanks for marking brainliest
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