Question

(n+1)+(n+2)+(n+3)......+2n

Answer 1

Answer:

The given sequence is in AP

First term=(n+1)

Common difference=1

Let the number of terms be x

n+1+(x-1)1=2n

(x-1)=n-1

x=n

Sum=n/2(n+1+2n)=n/2(3n+1)

=(3n^2+n)/2

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