Question

n-1
n - 2 n-3
n-4
+... n पदों तक (to n tern
(ii)
+
n
72
п
n​

Answer 1

Answer:

sum_(n=1)^oo(tan^-1((4n),(n^4-2n^ 2+2))) is equal to (A) tan ^-1 (2)+tan^-1 (3) (B) 4tan^-1 (1) (C) pi,2 (D) sec^-1(-sqrt2)

Answer 2

Answer:

(i) (n-1)/2 will be the answer