(n-10)2 + (10-n) factorise the term
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Answered by
2
(n-10)2 + (10-n) = 0
2n-20+10-n = 0
n-10 = 0
n = 10
2n-20+10-n = 0
n-10 = 0
n = 10
Answered by
2
(n-10)2 + (10-n) =0
2n-20+10-n =0
n-10 =0
n =10
therefore value for 'n' is 10
2n-20+10-n =0
n-10 =0
n =10
therefore value for 'n' is 10
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