Question

(n^2+1) -n^2 equals ?

1) n- (n+1)
2) (n+1) -n
3) (n-1) +n
4) (n+1) +n

Answer 1

Answer:

2) (n+1)-n

Step-by-step explanation:

$( {n}^{2} + 1) - {n}^{2} \\ = {n}^{2} + 1 - {n}^{2} \\ = 1 \\ \\ and \: (n + 1) - n \\ = n + 1 - n \\ = 1$