n/2(2×-16d+n-1×d)=0 find n
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The value of n=33. Hope it helps you.
Step-by-step explanation:
n/2[2(-16d)+(n-1)d]=0
=>n[-32d+nd-d]=2×0
=>(nd-33d)=0/n
=>d(n-33)=0
=>n-33=0/d
=>n=33.
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