n^2 + 20 find first 3 terms?
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1
Let a series of integers is represented by the equation: n^2 + 20
Therefore, to calculate three terms of this series n should be equal to1, 2 and 3 respectively.
So,
1st term = n^2 + 20 = 1^2 + 20 = 21
2nd term = 2^2 + 20 = 4 + 20 = 24
3rd term = 3^2 + 20 = 9 + 20 = 29
Answered by
0
let n=0,1,2
n=0
=0^3+30
=0+20
=20
n=1
=1^2+20
=1+20
=21
n=2
=2^2+20
=4+20
=24
therefore , the first 3terms are 20,21,24
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