n^2 + 241n -18600
Factorise the equation.
Answers
Answer:
The first term is, n2 its coefficient is 1 .
The middle term is, +241n its coefficient is 241 .
The last term, "the constant", is -9972
Step-1 : Multiply the coefficient of the first term by the constant 1 • -9972 = -9972
Step-2 : Find two factors of -9972 whose sum equals the coefficient of the middle term, which is 241 .
-9972 + 1 = -9971
-4986 + 2 = -4984
-3324 + 3 = -3321
-2493 + 4 = -2489
-1662 + 6 = -1656
-1108 + 9 = -1099
-831 + 12 = -819
-554 + 18 = -536
-277 + 36 = -241
-36 + 277 = 241 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -36 and 277
n2 - 36n + 277n - 9972
Step-4 : Add up the first 2 terms, pulling out like factors :
n • (n-36)
Add up the last 2 terms, pulling out common factors :
277 • (n-36)
Step-5 : Add up the four terms of step 4 :
(n+277) • (n-36)
Which is the desired factorization
THE ANWER IS (n + 277) • (n - 36)
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