Question

n^2+3n-40 factorise the following

Answer 1

Hi.

QUESTION

FACTORISE

✏ n² + 3n - 40

==> n² + 8n - 5n - 40 ......{SPLITTING THE MIDDLE TERM}

==> n(n + 8) - 5(n + 8)

==> (n - 5)(n + 8)

HENCE,

FACTORISED.


HOPE IT HELPS YOU.

Answer 2

$\boxed{\boxed{\large\mathbf{(x + 8)(x - 5)}}}$
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$\underline{\underline{\huge\mathfrak{ANSWER}}}$

$\mathsf{n^2 + 3n - 40}$

$\underline\text{Using the Formula},$

$\mathbf{(z + a)(z + b) = z^2 + (a + b)z + ab}$

$\mathbb{SPLITTING \ \ THE \ \ MIDDLE \ \ TERM}$

We need to find 2 numbers, whose

$\mathsf{Sum \ = 3}$
$\mathsf{Product \ = -40}$

Now,
[8 + (-5) = 3]

And,
[8 $\times$ (-5)= -40]

Hence, 8 and (-5) satisfy the given conditions.

$\mathsf{\Longrightarrow (x + 8)(x -5) }$

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$\large\boxed{\large\boxed{\large\boxed{\Huge\mathbb{THANKS}}}}$

$\huge\mathbf{\# \: Be \: Brainly}$