Question

N=2^4x3x7^5
PN=K, where P is an integer and K is a square number.Find the smallest value of P.

Answer 1

Answer:

the smallest value of P be 21

Step-by-step explanation:

here k is square number .

let k = $x^{2}$ for some number x

now , N = 2^4 × 3 × 7^5 = (4^2 × 49^2) ×3 ×7 = (4 × 49)^2 × 3×7

so if the smallest value of P be (3 × 7) then K = PN will be a square number .

hence smallest value of P be (3×7) = 21

Answer 2

Answer:

Step-by-step explanation:

I'm unsure what the marking scheme says but I think P is zero.

0 is considered an integer as it's a whole number .

It's also considered a perfect square since 0²=0

1. 0 x 2^4 x 3 x 7^5 = 0,as anything multiplied by 0 is equal to 0
2. K=0,which is a perfect square
3. P=0,as 0 is an integer: it's also obviously the smallest possible value since negative numbers can't be square rooted to give a viable answer.