Question

n ²-61n +900=0
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Answer 1

EXPLAINED CLEARLY IN THE PICTURE

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Answer 2

$\huge{\star}{\underline{\boxed{\red{\sf{Answer :-}}}}}{\star}$

Given :-

$\bf{ {n}^{2} - 61n + 900 = 0 }$

a = 1, b = -61 and c = 900

To Find :-

Value of n.

Solution :-

We know that,

$\huge{\boxed{\blue{\sf{D = b^{2} - 4ac}}}}$

_________[Put Values]

D = (-61)² - 4(1)(900)

D = 3721 - 3600

D = 121

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√D = 11

$\huge{\boxed{\blue{\sf{x = \frac{ - b \: \pm \: \sqrt{D} }{2a} }}}}$

When √D is positive then,

x = (61 + 11)/2

x = 72/2

x = 36

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When √D is negative then,

x = (61 - 11)/2

x = 50/2

x = 25