Question

N
2.
A point charge Q is kept at a point (0, 0, a/2) as shown in the figure.
Find the electrostatic flux through surface OABO.
Charge +04 (0, 0, a/2)
Q
1280
(A)
(B)
680
(0, a 12,0)
(C)
(D)
4860
в у
2460
(al 2, 0, 0)
A​

Answer 1

Electrostatic flux:

To find the electrostatic flux through surface OABO, we can use Gauss's Law. Gauss's Law states that the flux of an electric field through a closed surface is equal to the charge enclosed by that surface divided by the permittivity of the medium.

In this case, the surface OABO is a rectangular surface enclosing the point charge Q at (0, 0, $\frac{a}{2}$). The flux through this surface can be calculated as:

Flux = (Charge enclosed) / (Permittivity of the medium)

Since the point charge Q is enclosed by the surface, the charge enclosed is Q.

The permittivity of the medium is denoted by ε.

Therefore, the flux through surface OABO is given by:

Flux = Q / ε

The given answer options (+04, 1280, 680, 4860, and 2460) seem to represent possible values for the flux, but without the specific value of the charge Q and the permittivity of the medium, it is not possible to determine the exact value of the flux or select the correct answer option.

For more such questions on Electrostatic flux:

https://brainly.in/question/10013244

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