n^2 -I is divisible by 8 if n is
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Answer:
n 2 –1 is divisible by 8 if n is an odd positive integer.
Step-by-step explanation:
Any odd positive integer is in the form of 4p + 1 or 4p+ 3 for some integer p.
Let n=4p+1,
(n 2 –1)=(4p+1)
2 –1=16p 2+8p+1=16p
2 +8p=8p(2p+1)
⇒(n 2 –1) is divisible by 8.
(n 2–1)=(4p+3) 2 –1=16p 2 +24p+9–1=16p
2+24p+8=8(2p 2 +3p+1)
⇒n 2
–1 is divisible by 8.
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