Question

n 2021 population of a city is 11,57,625, if the population is increasing by the rate of 5% per annum compounded annually. Find the population of the city in the year 2018? please fast​

Answer 1

Answer:

506250

Step-by-step explanation:

Solution :

Let the population before 2 years was x. 2

The rate of increase of population = 6% per 63 20 annum. = % per annum. 3 .. The population of the town in present year

20 3 100 2 =XX 1+ - ( ₁ + 1²/13) ² 2 = X X 15

= X X

16 15 2 16 x 16 15 x 15 16 × 16 15 x 15 = X X As per question x x 576000

576000 x 15 x 15 ⇒ x = = 506250

16 × 16

Hence the population of the town before 2 years was 506250.

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Answer 2

ANSWER:901428.696

Step-by-step explanation:

current population=1157625

rate =5%

It is in decrease as we are taking about past

time =2021-2018=3yrs

so equation=

A=P(1-R/100)n

A=1157625(1-5/100)³

A=1157625(95/100)³

A=901428.696

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