Question

N =2p-3,p ∈ N and divide n² by 4 what will be the remainder?​

Answer 1

Step-by-step explanation:

If the first part = p1; the second part = p2 and the third part = p3 then

N = p1+p2+p3

N-p3 = p1+p2

p1+p2 = p3 * K * 0.01* N

p3 * K * 0.01* N = p1 + p2

p3 * 0.01 * K * N = p1 + p2

p3 = (p1 + p2) / 0.01* K * N

p3 = (p1+p2) / (0.01 * K * N)

p3 = 100 * (p1+p2) / (K*N)