History, asked by anjaligaikwad34959, 8 months ago

n 3.1 = 0m0 d)n = 3,1 = 2, m = 2,£1,0
13. The wave number of the shortest wavelength transition in Balmer series of atomic hydrogen will
a) 42154 b) 1437 A )3942 A d) 3647 A​

Answers

Answered by jeetendralalch
0

42154 is the correct answer

Answered by shristi2249
4

Answer:

42154 is the correct answer

thankyou

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