Math, asked by abhinavdas9thcbsetim, 2 months ago

N=(3+1) (3² + 1) (34 + 1) (38 + 1) (364 + 1). If N can be simplified as (3^a-1)/2 then find the value of a.​

Answers

Answered by rubansebastian3
0

Answer:

Step-by-step explanation:

1+(3+1)

 (32+1)

(34+1)

(38+1)

(316+1)

(332+1)

=1+12[(3−1)(3+1)(32+1)(34+1)(38+1)(316+1)(332+1)]

=1+12[(32−1)(32+1)(34+1)(38+1)(316+1)(332+1)]

=1+12[(34−1)(34+1)(38+1)(316+1)(332+1)]

=1+12[(38−1)(38+1)(316+1)(332+1)]=1+12[(316−1)(316+1)(332+1)]=1+12[(332−1)(332+1)]=1+12[(364+1)]=2+364−12=364+12

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