N=(3+1) (3² + 1) (34 + 1) (38 + 1) (364 + 1). If N can be simplified as (3^a-1)/2 then find the value of a.
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Answer:
Step-by-step explanation:
1+(3+1)
(32+1)
(34+1)
(38+1)
(316+1)
(332+1)
=1+12[(3−1)(3+1)(32+1)(34+1)(38+1)(316+1)(332+1)]
=1+12[(32−1)(32+1)(34+1)(38+1)(316+1)(332+1)]
=1+12[(34−1)(34+1)(38+1)(316+1)(332+1)]
=1+12[(38−1)(38+1)(316+1)(332+1)]=1+12[(316−1)(316+1)(332+1)]=1+12[(332−1)(332+1)]=1+12[(364+1)]=2+364−12=364+12
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