n=3 m=0 I=1 s=-1/2 then find element name and atomic no
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n = 3 means third shell
I = 0 means s subshell of third shell.
m = 0 means either 3s has I or 2 electrons
∴ Electronic configuration is
Is 2,2s 2,2P 6,3S 1or 3S 2
∴ Atomic number is 11 or 12
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Answer:
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