Question

n+3p6: n+2p4 =14 find n .

Answer 1

hello mate here is your answer ↓

АиЗшЕГ↓

14*nP3 = (n+2)P4

solotion !

thus 14n(n-1)(n-2) = (n+2)(n+1)(n)(n-1)  

cancelling out common terms,  

14(n-2) = (n+2)(n+1)  

opening out & collecting terms  

n² -11n + 30 = 0  

factorising  

(n-5)(n-6) = 0  

solutions are n = 5 or n = 4

if this helps mark braliest in follow me !

Answer 2

Answer:

n=4

Step-by-step explanation:

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