Math, asked by mithukole990, 9 months ago

n/4-1/8=n/20+3/4
Please help

Answers

Answered by Itzraisingstar
1

Answer:

Step-by-step explanation:

n/4-1/8=n/20+3/4,

take them as L.H.S and R.H.S,

L.H.S=n/4-1/8,

L.C.M of 4,8,

8.

So,n×2-1×1,

2n-1.

R.H.S=n/20+3/4,

L.C.M of 20,4,

20,

so,n×1,3×5,

n+15.

Substitute tha values

2n-1=n+15,

n=16.

hope it helps.

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