n+5=19(n=1)
answer me please
Answers
Step-by-step explanation:
Eliminate redundant parentheses
+
5
=
1
9
(
=
1
)
n+5=19(n=1)
n+5=19(n=1)
+
5
=
1
9
⋅
=
1
n+5=19 \cdot n=1
n+5=19⋅n=1
2
Subtract
5
5
5
from both sides of the equation
+
5
=
1
9
⋅
=
1
n+5=19 \cdot n=1
n+5=19⋅n=1
+
5
−
5
=
1
9
⋅
=
1
−
5
n+5{\color{#c92786}{-5}}=19 \cdot n=1{\color{#c92786}{-5}}
n+5−5=19⋅n=1−5
3
Simplify
Subtract the numbers
=
1
9
⋅
=
1
−
5
n=19 \cdot n=1-5
n=19⋅n=1−5
4
Subtract
1
9
⋅
=
1
19 \cdot n=1
19⋅n=1
from both sides of the equation
=
1
9
⋅
=
1
−
5
n=19 \cdot n=1-5
n=19⋅n=1−5
+
1
9
⋅
=
1
(
−
1
)
=
1
9
⋅
=
1
−
5
+
1
9
⋅
=
1
(
−
1
)
n+{\color{#c92786}{19 \cdot n=1\left(-1\right)}}=19 \cdot n=1-5+{\color{#c92786}{19 \cdot n=1\left(-1\right)}}
n+19⋅n=1(−1)=19⋅n=1−5+19⋅n=1(−1)
5
Simplify
Multiply the numbers
Multiply the numbers
Combine like terms
−
1
9
⋅
=
1
=
−
5
6×3+1 = 19
Step-by-step explanation:
5+1=6
19-1 equal 18
6×6/2+1=19