Question

N.7. A stone is thrown up to a height of 100mts with a velocity of 20m/s. Instantaneously, another stone is dropped from the same height. Calculate when and where will the two stones meet?​

Answer 1

Answer:

.

:

′

=0

=0+

2

1

2

=

2

1

×10×

2

⟹=5

2

............(1)

:

=25 /

100−=−

2

1

2

100−=(25)−

2

1

×10×

2

⟹100−=25−5

2

............(2)

(1) (2),

25=100

⟹=4

(1),

=5×4

2

⟹=80

20 4 .

Explanation: