Question

n(~)= 80, n (A) = 48 ,n ( B) = 40 and n(A n B) = 25, then n ( AUB)' =?

Answer 1

Answer:

n(AUB)=n(A)+n(B)-n(A n B)

=48+40-25

=63

therefore n(AUB)'=n(~)-n(AUB)

=80-63

=17

Step-by-step explanation:

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Answer 2

Answer:

( AUB)' = n(A)+n(B)-n(AnB)

= 48+40-25

= 88-25

= 65

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