Question

n(A)=10, and n(A⋂B)=3 , find n((A⋂B)'⋂A)​

Answer 1

Step-by-step explanation:

10×

4

1

=

4

14

25 \times \frac{3}{4 } = \frac{79}{4}25×

4

3

=

4

79

16 \times \frac{1}{2} = \frac{18}{2}16×

2

1

=

2

18

\frac{14}{4} + \frac{79}{4} + \frac{18}{2}

4

14

+

4

79

+

2

18

\green l \green c \green m = 4lcm=4

\frac{14}{4} \times \frac{1}{1} = \frac{14}{4}

4

14

×

1

1

=

4

14

\frac{79}{4} \times \frac{1}{1} = \frac{79}{4}

4

79

×

1

1

=

4

79

\frac{18}{2} \times \frac{2}{2} = \frac{36}{4}

2

18

×

2

2

=

4

36

\frac{14}{4} + \frac{79}{4} + \frac{36}{4}

4

14

+

4

79

+

4

36

\frac{14 + 79 + 36}{4}

4

14+79+36

\frac{129}{4}

4

129

Answer 2

Answer:

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