Question

n(A)=12,n(B)= 3, n(A intersection B)=3 then
n[(A×B) intersection (B×A)]= ??​

Answer 1

Answer:

given:(A intersection B)=3

=n(A union B)=n(A)+n(B)-n(A intersection B)

=n(A union B)=12+3-3

=n(A union B)=12

therefore

={12,12}

I am not sure