Question

n(A)=14,n(B)=10 and n( Aunion B ) = 18 find n(A intersecting B )

Answer 1

Answer:

6

Step-by-step explanation:

n(A union B) = n(A) + n(B) - n(A intersecting B)

I hope it helps

Answer 2

Answer:

$\rm \sf{n(a) = 14}$

$\sf {n(b) = 10}$

$\sf{n(a \: union \: b) = 18}$

$\boxed{\rm \pink{now}}$

$\sf{n(a \: unionb) = n(a) + n(b) - n(a \: intersection \: b)}$

$\sf{n(a \: intersection \: b \: ) = n(a) + n(b) - n( a \: union \: b \: )}$

$\boxed{\rm \purple{14 + 10 - 18}}$

$\boxed {\rm \purple{24 - 18}}$

$\boxed{ \rm \purple{6}}$

$\red{▬▬▬} \green{▬▬▬}\blue{▬▬▬} \orange{▬▬▬}$