Question

n(A)=14,n(B)=10,n(Aunion B)=18 find n(A intersection B)​

Answer 1

Step-by-step explanation:

Given :-

n(A) = 14

n(B) = 10

n(AUB) = 18

To find:-

Find n(AnB) ?

Solution:-

Given that :

n(A) = 14

n(B) = 10

n(AUB) = 18

We know that

n(AnB) = n(A)+n(B)-n(AUB)

On Substituting these values in the above formula then

=> n(AnB) = 14 + 10 -18

=> n(AnB) = 24 - 18

=>n(AnB) = 6

Answer:-

The value of n(AnB) for the given problem is 6

Used formulae:-

• n(AnB) = n(A)+n(B)-n(AUB)

• It is called Fundamental Theorem on sets.

• n(A)=number of elements in the set A

• n(B)=number of elements in the set B

• n(AUB)=number of elements in AUB

• n(AnB)=number of elements in AnB