Question

n(A)=15, n(AUB)=29, n(AnB)=7
complete the following activity to find n(B).​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Given:

n(a)=15

$\sf \: n(a\cup ba∪b )=29$

$\sf \: n(a\cap ba∩b )=7$

To find:

n(b)

Solution:

We know that

$\boxed{ \sf \: n(a\cup ba∪b )=n(a)+n(b)-n(n\cap bn∩b )}$

To find the value of b we are using the above formula

Now, substitute the values then, we get

$\boxed{ \sf29=15+n(b)-729=15+n(b)−7}$

$\boxed{ \sf \: n(b)=29-15+7n(b)=29−15+7}$

$\boxed{ \sf \: n(b)=21n(b)=21}$

$\sf \: (b)=21$

Hence, the value of n(b)=21