Question

n(A)=15,n (AUB)=29,n (AnB)=7,then n (B)=?

Answer 1

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Given that :

n(A) = 15

n(A∪B) = 29

n(A∩B) = 7

To find n(B) ,

By Fundamental theorem of Sets :

→ n(A∪B) = n(A) + n(B) - n(A∩B)

29 = 15 + n(B) - 7

29 = 8 + n(B)

n(B) = 29-8

∴ n(B) = 21

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