n(A)=285, n(B)=195, n(U)=500, n(AUB)=410 , find n(A'UB')
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3
the answer is...
215+305= 520
215+305= 520
Answered by
1
n(AUB) = n(A) + n(B) - n(A n B)
410 = 285 + 195 - n(AnB)
n(AnB) = 285 + 195 - 410
= 70
n(AnB)' = U - n(AnB)
= 500 - 70 = 430
By Demorga's Theorem
n(A' U B') = n(A n B)'
= 430
410 = 285 + 195 - n(AnB)
n(AnB) = 285 + 195 - 410
= 70
n(AnB)' = U - n(AnB)
= 500 - 70 = 430
By Demorga's Theorem
n(A' U B') = n(A n B)'
= 430
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