Question

N(a)=30, n(b)=45, n(a∪b)=65 then find 1) n(a∩b) 2)n(a–b) 3) n(b–a)

Answer 1

Step-by-step explanation:

N(a)=30, n(b)=45, n(a∪b)=65

1) we know that,n(aUb)=n(a)+n(b)-n(a∩b)

=>65=30+45-n(a∩b)

=>65=75-n(a∩b)

=>-10=-n(a∩b)

n(a∩b)=10

(2)n(a-b)=n(a)-n(a∩b)

n(a-b)=30-10

n(a-b)=20

(3)n(b-a)=n(b)-n(a∩b)

n(b-a)=45-10

n(b-a)=35

Answer 2

Answer:

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