Question

n(A) =30 n(B)=45 n(A union B) =65 then find n(A intersection B)​

Answer 1

Answer:

n(A∩B) = 10

Step-by-step explanation:

n(AUB) = n(A) + n(B) - n(A∩B)

Then, n(A∩B) = n(A) + n(B) - n(AUB)

                       = 30 + 45 - 65

                       = 75 - 65

                        = 10

Answer 2

Answer:

there fore n of A =30,n of B=45 and n of A union B =65then A intersection B =?

A+B-(A union B)=30+45-65=75-65=10 then A intersection B is 10