n(A)=45,n(B)=52,n(AUB)= 70 find n (AnB)=?
Answers
Answered by
38
n(AUB)=n(A)+n(B)-n(A∩B)
70 = 45+52 -n(A∩B)
n(A∩B) = 70-97 = -27
Answered by
45
Here is the solution :
There is a mathematical relation between union and intersection of Two sets,
Let A and B be two sets, Then the formula will be,
n(AUB) = n(A)+ n(B) - n(AnB),
Given data,
n(A) = 45,
n(B) = 52,
n(AUB) = 70,
n(AnB) = ?,
Substituting them in above Formula,
=> 70 = 45 + 52 - n(AnB),
=> 70 = 97 - n(AnB),
=> n(AnB) = 97-70,
=> n(AnB) = 27,
Therefore : The a answer is 27,
Hope you understand, Have a Great day :D,
Thanking you, Bunti 360 !.
There is a mathematical relation between union and intersection of Two sets,
Let A and B be two sets, Then the formula will be,
n(AUB) = n(A)+ n(B) - n(AnB),
Given data,
n(A) = 45,
n(B) = 52,
n(AUB) = 70,
n(AnB) = ?,
Substituting them in above Formula,
=> 70 = 45 + 52 - n(AnB),
=> 70 = 97 - n(AnB),
=> n(AnB) = 97-70,
=> n(AnB) = 27,
Therefore : The a answer is 27,
Hope you understand, Have a Great day :D,
Thanking you, Bunti 360 !.
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