n (A)=5;n (B)=6 n (A union B)= 9 and n (A intersection B)= ?
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we know that:
n(A union B)=n(A)+ n(B)-n(A intersection B)
n(A intersection B)=n(A)+n(B)-n(A union B)
given that:
n(A)=5
n(B)=6
n(A Union B)= 9
put these values we get ,
n(A intersection B)=5+6-9=11-9=2.
(A intersection B)= 2.
This is your answer I hope this will be right answer.
please mark me brainliest.
and thank you for asking.
n(A union B)=n(A)+ n(B)-n(A intersection B)
n(A intersection B)=n(A)+n(B)-n(A union B)
given that:
n(A)=5
n(B)=6
n(A Union B)= 9
put these values we get ,
n(A intersection B)=5+6-9=11-9=2.
(A intersection B)= 2.
This is your answer I hope this will be right answer.
please mark me brainliest.
and thank you for asking.
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