n (A)=5,n (B)=8,n (A intersection B)=3 ,find n (A union B)
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n ( A U B ) = n ( A ) + n ( B )
- n ( A n B )
Given : n ( A ) = 5 n ( B ) = 8
n ( A n B ) = 3
n ( A U B ) = 5 + 8 -3
=13-3
= 10
Therefore n ( A U B ) = 10
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