n(A) = 5, N(B) = 9 and n( A Ս B) =21 then n ( A ∩ B) =
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7 is the answer of the question
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n(AUB) = n(A) + n(B) - n(A intersection B)
21 = 5 + 9 - n (A intersection B)
21 - 14 = - n(A intersection B)
- 5 = n(A intersection B)
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