Question

n(A)=50,n(B)=20 andn(A intersection B)=10
then n(A∆B)is

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Answer 1

The value of n (A ∪ B) is 60.

Step-by-step explanation:

The number of outcomes of the union of events is:

$n(X\cup Y)=n(X)+n(Y)-n(X\cap Y)$

The information provided is:

n (A) = 50

n (B) = 20

n (A ∩ B) = 10

Compute the value of n (A ∪ B) as follows:

$n(A\cup B)=n (A)+n (B)-n(A\cap B)$

               $=50+20-10\\=60$

Thus, the value of n (A ∪ B) is 60.