Question

n(A) = 8 , n(B) = 9 , n(A∩B) = 6 where A and B are to sets then n(A∪B)=

Answer 1

Answer:

11

Step-by-step explanation:

8+9-6 = 11

n of a plus n of b minus n of a intersection b

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Answer 2

n(AUB)=11

Step-by-step explanation:

n(AUB)= n(A)+n(B)-n(AnB)