n a ΔABC if ∠A=45 and ∠B=70 determine the shortest and largest sides of the triangle
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According to question,
<A+<B+<C=180°. (sum of all angles of a ∆=180°)
now ,
45°+70°+<C=180°
=) 115°+<C=180°
=) <C=180°-115°
=) <C=65°
Shortest side=BC (This side is facing the smallest angle i.e=45°) and Longest side=AC(this side is facing the largest angle i.e=70°)
hope this ll be helpful for u..
<A+<B+<C=180°. (sum of all angles of a ∆=180°)
now ,
45°+70°+<C=180°
=) 115°+<C=180°
=) <C=180°-115°
=) <C=65°
Shortest side=BC (This side is facing the smallest angle i.e=45°) and Longest side=AC(this side is facing the largest angle i.e=70°)
hope this ll be helpful for u..
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