n(A-B)=13,n(B-A)=17,n(A)=?
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n (A - B) = 13
n (B - A) = 17
n (A ∪ B) = 36
n (A ∩ B) = ?
Since, we know that "A∩B" is the set containing all the elements present in both set A and set B. In this case, there are 4 elements which are present in both A and B
So, n (A ∩ B) = 4
HOPE THIS HELPS YOU!!! ❤❤❤
n (A - B) = 13
n (B - A) = 17
n (A ∪ B) = 36
n (A ∩ B) = ?
Since, we know that "A∩B" is the set containing all the elements present in both set A and set B. In this case, there are 4 elements which are present in both A and B
So, n (A ∩ B) = 4
HOPE THIS HELPS YOU!!! ❤❤❤
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Answered by
1
Given n(A-B)=13
And n(B-A)=17
Divide equation 1by 2 to eliminate n
![\frac{n(a - b)}{n(b - a)} = \frac{13}{17} \frac{n(a - b)}{n(b - a)} = \frac{13}{17}](https://tex.z-dn.net/?f=+%5Cfrac%7Bn%28a+-+b%29%7D%7Bn%28b+-+a%29%7D++%3D++%5Cfrac%7B13%7D%7B17%7D+)
....
And n(B-A)=17
Divide equation 1by 2 to eliminate n
....
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