N a culture of bacteria, a sample is taken at 10:00am and contains 1000 cells per ml. A second sample at 8:00pm has 10,000 cells per ml. What is the generation time ?
Answers
Answer:
Solve for n:
logb = logB + nlog2
n = logb - logB
log2
n = logb - logB
.301
n = 3.3 logb/B
G = t/n
Solve for G
G = t
3.3 log b/B
Example: What is the generation time of a bacterial population that increases from 10,000 cells to 10,000,000 cells in four hours of growth?
G = t_____
3.3 log b/B
G = 240 minutes
3.3 log 107/104
G = 240 minutes
3.3 x 3
G = 24 minutes
Given:
The concentration of bacteria at 10:00am (t=0) = Bo = 1000cells/ml
The concentration of bacteria at 8:00pm (t=t) = B = 10000cells/ml
To Find:
The generation time
Solution:
We know that bacterial growth is exponential because each bacteria divides and give rise to one more bacteria which can further divide.
B = Bo X 2ⁿ
Here, n= the number of generations
Substituting the values,
10000 = 1000 X 2ⁿ
Taking log of both sides,
log (10000) = log (1000) + n log 2
or 4 = 3 + n (0.30)
or n = 4-3 / 0.30
= 1/0.30
The generation time = Total time / n
Here total time = 10 hours
So generation time = 10 X 0.30 = 3 hours
Hence, the generation time is 3 hours.