Question

N a town, the population was 8000. in one year, male population increased by 10% and female population increased by 8% but the total population increased by 9%. the number of males in the town was:

Answer 1

let number of women be
x
x and men be
(
5000
−
x
)
.
5000x Then,
10
×
5000
−
x
100
+
15
×
x
100
=
(
5600
−
5000
)
105000x10015x10056005000

after solving this equation
we get
10000
+
x
=
600
×
20
10000x60020
x
=
2000
x2000

so we get, number of women is
2000
2000
then number of men will be
3000
3000
so answer is
3000