Question

n(a union b) = 40
n(a intersection b) = 8
n(a-b)=n(b-a)
find A and B​

Answer 1

Step-by-step explanation:

BY GIVEN INFORMATION,

WE KNOWN THAT ,

A UNION B = 40

A INTERSECTION B=8

A-B=B-A......1

THEREFORE, A+A=B+B.....FROM1

THEREFORE 2A=2B

THEREFORE, A=B.......2

n(A UNION B)=n(A)+n(B)-n(A INTERSECTION B)

40=n(A)+n(B)-8......PUTTING VARIABLE IN BOTH SIDE

n(A)+n(B)=48

2n(A)=48.........From2

n(A)=24.

n(B)=24.

THEREFORE, A AND B BOTH ARE 24.